Question

Someone please help
Elimination
{ x + y – 2z = 8
{5x – 3y + z =-6
{-2x – y + 4z = -13


Substitution
{3x + y = 2z =22
{x + 5y + z =4
{x = -3z + 6

Answer 1

I can solve the second one for you..but the first equation is messed up.

You put: 3x + y = 2z =22

There are 2 equal signs.

Answer 2

Can you fix that? @-EtherealEbullience

Answer 3

{3x + y - 2z =22
{x + 5y + z =4
{x = -3z + 6

Answer 4

Okay, we need to change the first equation.

3x + y - 2z = 22

Add 2z to both sides:

3x + y = 2z + 22

Subtract 3x to both sides:

y = -3x + 2z + 22

Answer 5

elimination :

x + y - 2z = 8
-2x - y + 4z = -13
-----------------add
-x + 2z = - 5

x + y - 2z = 8 ---->(3)
5x - 3y + z = -6
---------------
3x + 3y - 6z = 24 (result of multiplying by 3)
5x - 3y + z = -6
--------------add
8x - 5z = 18

-x + 2z = -5 --->(8)
8x - 5z = 18
-----------
-8x + 16z = -40 (result of multiplying by 8)
8x - 5z = 18
-----------add
11z = - 22
z = -2

-x + 2z = -5
-x + 2(-2) = -5
-x - 4 = -5
-x = -5 + 4
-x = -1
x = 1

x + y - 2z = 8
1 + y - 2(-2) = 8
1 + y + 4 = 8
5 + y = 8
y = 8 - 5
y = 3

solution is : x = 1, y = 3, and z = -2

Answer 6

Gosh. . .That's a long process. /.\