Question

(1, 0) is an ordered pair of the function f(x) = 1 + x.

Answer 1

Example:
Find f(0), f(1), f(
-
2), f(
-
x),
-
f(x), f(x+1), f(2x), f(x+h)
for f(x) = 3x
2
-
2x
–
4
f(
0
) = 3(
0
)
2
-
2(
0
)
–
4 =
-
4
f(
1
) = 3(
1
)
2
–
2(
1
)
–
4 =
-
3
f(
-
2
) = 3(
-
2
)
2
-
2(
-
2
)
-
4= 12
f(
-
x
)
=
3(
-
x
)
2
-
2(
-
x
)
-
4 = 3x
2
+ 2x
–
4
f(
x+1
) = 3(
x+1
)
2
-
2(
x+1
)
–
4 = 3(x
2
+ 2x +1)
-
2x
-
2
-
4 = 3x
2
+ 6x + 3
-
2x
–
6= 3x
2
+ 4x
–
3
f(
2x
)
= 3(
2x
)
2
-
2(
2x
)
–
4 = 3(4x
2
)
–
4x
–
4= 12x
2
–
4x
–
4
f(
x+h
) = 3(
x+h
)
2
-
2(
x+h
)
–
4 = 3(x
2
+ 2xh +h
2
)
–
2x
-
2h
-
4 = 3x
2
+ 6xh + 3h
2
-
2x
–
2h
–
4
-
f(x)
=
-
(3x
2
–
2x
–
4) =
-
3x
2
+ 2x+4

Answer 2

please give me a medel

Answer 3

i just did

Answer 4

thx

Answer 5

welcome (: