Question

Let f(x) = x + 2 and g(x) = x2 Find ( g o f)(-5

Answer 1

\[(g\circ f)(x) = g(~f(x)~)\]
So since \(g(\mathbf{\color{red}{x}}) = \mathbf{\color{red}{x}}^2\); What is \(g(\mathbf{\color{red}{f(x)}})\)?

Answer 2

I would first plug -5 in f(x) to solve for f(-5), then plug that value in g(x)

Answer 3

ok.... i'm sorry i don't understand it

Answer 4

Can you find what is \(f(-5)\)?