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If you help, I will fan and medal :) Start from 110 feet away, a person on a scooter rides towards a checkpoint and then passes it. The rider is traveling at a constant rate of 30 feet per second. The distance between the scooter and the checkpoint is given by the equation d=(110-30t). At what seconds is the bike 40 feet away from the checkpoint?
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a.) 2.3 sec and 5 sec b.) 1.6 sec and 5 sec c.) 2.3 sec and 4.6 sec d.) 1.6 sec and 4.6 sec
c i'm pretty sure
@SureStarFire Thank you!
because it is 40 meters away from 110 meters which is 2 seconds at 30 feet per second and 0.333333333...
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