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Mathematics
OpenStudy (anonymous):

Find all solutions to the equation. sin^2x + sin x = 0

OpenStudy (anonymous):

sin^2(x)+sin(x)=0 sin(x)(1+sin(x))=0 soo sin(x)=0 or sin(x)=-1 x=pi*n x=2pi*n+3pi/2 x=2pi*n -pi/2

OpenStudy (anonymous):

Okay I get that @peterek0. So when I look on the unit circle, I would be looking for 3pi/2 for my solutions?

OpenStudy (anonymous):

n is any intiger. There are infinite amount of solutions .

OpenStudy (anonymous):

Thank you.

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