Find the equation of the quadratic function with zeros -1 and 1 and vertex at (0, -4).

y = x2 + 1

y = x2 - 1

y = 4x2 - 4

y = 4x2 + 4x

Question

Find the equation of the quadratic function with zeros -1 and 1 and vertex at (0, -4).
		
y = x2 + 1
		
y = x2 - 1
		
y = 4x2 - 4
		
y = 4x2 + 4x

anonymous · Answer

@van_lynne any attempts? What do you need help with specifically or are you lost all together?

anonymous · Answer

im completely lost

anonymous · Answer

@Algorithmic

anonymous · Answer

Are you familiar with quadratic equations? As in have you ever used the quadratic formula?

anonymous · Answer

no

anonymous · Answer

All right, how about factoring? That is one of the basics they teach before they teach quadratic equations to anyone. Do you know how to factorize equations?

anonymous · Answer

Actually we could solve this by graphing, do you know how to graph linear equations? It is really simple and I can teach it to you easily if you would like.

mathmath333 · Answer

if u have to solve through options ,just put the points (0,-4)
in each of the four options and see if LHS=RHS

anonymous · Answer

Oh, I did not know that was possible. Neat trick.

anonymous · Answer

i still have no idea what the answer is :/

anonymous · Answer

To find the zeros of quadratic equation look at the x-axis where the parabola intercepts the x-axis is where the zeros of the quadratic equation are. (The vertex could be the spot of symmetry.)

anonymous · Answer

whats a parabola?

anonymous · Answer

A parabola is a two-dimensional, mirror-symmetrical curve which generally looks like the letter 'U'.

anonymous · Answer

Here perhaps this image would make more sense to explaining what I am trying to say.