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find (f)(g) if f(x) = 3x and g(x) = x + 1
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(3x)(x + 1) \[3x^2+3x\]
\(\bf f(x) = 3x \qquad g(x) = x + 1\qquad (f)(g) \implies (3x)(x + 1)\)
That's if you meant f(x) times g(x)
the options are 3x + 3 3x + 1 4x + 1 3x2 + 1
oh, then your question must have been f of g, which is f(g(x)) Which is: 3(x+1) = 3x + 3
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so its... 3x+1?
"3(x+1) = 3x + 3" So how did you get 3x+1?
its the closest lol, im just guessing. i dont understand this
It is 3x + 3. That's answer choice #1
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