checking answers, screenshots attached
first one look good
2nd one is also look good
Question : 6 is also looking fine.. \(3 <x < 6\)
3rd one is also looking fine to me.. :) Good, Well done..
yep good yah !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! :)
what about this one?
what you get when you solve first one which is 5a + 12 < 2
Calculate the same for first one.. For second you have got \(a < 3\), which is right..
@Nnesha the first one was a < -2 but that is clearly irrelevant because the second one was a < 3
only a few more(: thank you everybody
Yes, you are right, x = 5..
can someone walk me through this one please?
I think in that you have to write both, a < -2 as well as a < 3 too.. Are you given with any answer choices?
What do you think?
no, that one is something i have to write. i did write an explanation about the -2 tho beneath it
No..
@Nnesha i dont think so... the -2 is just irrelevant
a is in between -2 and 3 if a > -2 and a < 3 which is not the case here..
@Nnesha it is simple to check: For first one a < -2, let us take a = -1, it will not satisfy first inequality, as -1 is greater than -2 and not less than..
can someone please walk me through the one i asked?
yeah i understand thanks
ok so last one when you take a absolute value of a number you left with two answer positive and negative
See, for mods, one time you take positive and next time you take negative of it.. |3x|>= 21 It implies that: 3x >= 21 or -3x >= 21 Just solve the two inequalities..
ahhhh. gracias
now just solve for x be careful with second one
i have a few more if anyone here is still putting up with this crap haha
yep they all are right
@kah.x
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