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Identify the vertex by writing the equation in the standard form of a quadratic function. f(x)=x2−22x+116
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The x coordinate of the vertex for y = ax^2 + bx + c is given by this formula x = -b/(2a)
a = 1 and b = -22 in this case
so what is the x coordinate of the vertex?
1?
Im confused
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do you see how I found that a = 1 and b = -22
i do not
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