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a natural number when increased by 12 becomes equal to 160 times the reciprocal of given natural number . find the number
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let natural number=x
reciprocal=1/x
inc by 12 x+12=160*(1/x)
but then isn't it x+12
soo.. the equation would be say the natural number be 'x' x + 12 = 160/x...
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multiply both side by x
can u solve further ??
x(x+12)=160
Q says after increment it equals to 160 time the reciprocal of number and 1/x is reciprocal of the number
x^2+12x-160=0
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so rhs is 160/x or 160/x+12?
x^2+20x-8x-160=0 solve it now
when we add 12 to x x+12 it become equal to 160*(1/x) x+12=160/x
ok ill try from here thanks
is the answer x=8 and x+12=20
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??
x2 + 12x - 160 = 0 x2 + 20x - 8x - 160 = 0 (x+20) (x-8)= 0 x = -20 and x = 8
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