Solve the system of equations algebraically (using either substitution or elimination) 8x-2y=9 -12x+3y=5 I'm not sure how to use substitution and elimination won't work...
elimination can work but you have to multiply one of equation to get either x or y with same coefficient
How would yhu do that? 8 can't go into 12 and 2 can't go into 3...
yeah so multiply equation to get the equation balance but in your this question you have to multiply both equation
multiply first equation by 3 multiply second equation by 2 does it make sense ??
Then that would cancel out the y's.... I didn't know yhu could multiply both equations.... :o
O.o Wait, but if I multiplied by 2 and 3, it would also cancel out the x's because Id have a positive and negative 24...
|dw:1412980247428:dw| ohhh i just notice this
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