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-a2 - 3b3 + c2 + 2b3 - c2 if a = 3, b = 2, and c = -3.
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plug in the values given for a, b, and c and solve
i know .-. i did that, and it all came up wrong...
\[-a^2-3b^3+c^2+2b^3-c^2\]
yeah. that.
\[-(3^2)-3(2^3)+(-3^2)+2(2^3)-(-3^2)\]
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\[-(9)-3(8)+(9)+2(8)-(9)\]
\[-9-24+9+16-9\]
\[-17\]
Oh. i see what i did wrong. I made the first 9 positive
Thanks man :)
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np
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