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can someone please help me find the range of this function f(x) = (x - 2)2 + 2
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range means what output we will get from this
If you look at its grapg you see the range starts from 2 and goes to positve infinity...
whatever value of x we will put here that will give positive output
beacuse square make that positive
min value we will get at x=2
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So in interval notion that would be \[[2,\infty)\]
thank you i think i got it now
np
if f(x) = (x-2)2+2 then f(x) = (x^2) - 4x +6 With y intercept being 6 Range: All real numbers greater than 6 since the parabola's minimum value is 6. If you make a graph, you can clearly see it.
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