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OpenStudy (anonymous):
integration
why isn't e^cosx integrated into sinxe^cosx?
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hartnn (hartnn):
is derivative of
sin x e^cos x = e^ cos x ?
you know integration is also anti-derivative, right ?
hartnn (hartnn):
anyways
you can integrate e^cos x by trying
u =cos x
OpenStudy (anonymous):
yeah and sinx is differentiated into cosx right?
so cosx should be sinx
hartnn (hartnn):
correct
integral of cos x is indeed sin x + c
OpenStudy (anonymous):
so it should be 1/cosx instead?
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hartnn (hartnn):
because derivative of (sin x +c) is = cos x
hartnn (hartnn):
i doubt integral of e^cos x exist
even if it does, it won't be in terms of standard function
hartnn (hartnn):
what should be 1/cos x ?
OpenStudy (anonymous):
sorry i mean -1/sinx • e^cosx
as the integrate of e^cox because that's what i get...
OpenStudy (anonymous):
1/sinx ** not negative
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OpenStudy (anonymous):
ohs hoot they said to differentiate not integrate wow
i am so careless
but thanks for helping! ^^
hartnn (hartnn):
lol, no problem:)
welcome ^_^
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