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@hartnn
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There is a hole at x = –25. There is a removable discontinuity at x = 5. There is a vertical asymptote at x = 5. There is no discontinuity at x = 5.
what do u think ?
at x = 25 f(x) is not 0, hence there is no hole at x=25
see if you get vertical asymptote at x=5
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i think that 5 is a vertical asymptote
thanks(:
correct, welcome ^_^
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