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express the given quantity as a single logarithm (1/2)ln(x) - 5ln(x^9 +5)
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(m)ln(x) = ln(x)^m ln x - ln y = ln(x/y)
ln(x)^1/2 - ln(x^9+5)^5= ln((x)^1/2)/(x^9+5)^5)
is that right?
yup..:))))))
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is that right?
thanks a lot!
yeah...nd u r most welcome @swift_13
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