Question

help !!

Answer 1

A ball is dropped from a tower 350 meters above the ground with position function s(t) = 4.9t^2+ 350.

What is the velocity of the ball after 2 seconds?

Include units in your answer.

Answer 2

please explain! not just the answer!

Answer 3

velocity is change in distance divided by change in time
ds/dt

Answer 4

Velocity is derivative of motion equation, so you need to find \(s'(2)\)

Answer 5

do you know how to find the derivative of s(t) with respect to t ?

Answer 6

ohh

Answer 7

Can you do derivative?

Answer 8

omg too many people

Answer 9

\(\dfrac{d}{dt}s(t)\) = ?

Answer 10

ok