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hi how to appoximate natural logatim without caculator? for example: ln(8/37)?
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well \[\ln=\log_{e} \]
i know that ln in base on e
\[\ln \frac{ 8 }{ 37 }=\log8 +\log37\]
Minus, not plus
yer minus
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i mean how to approximate answer?
sorry minus
8=2^3
2^3=8 2^5=32
\[e \approx 2. \text{ blah}\]
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ln2=0.69
ok....in know that: 32<37<64 and ans is between 5*.69 and 6*.69 = 3.45 and 4.14 in mean which number between 3.45 and 4.14 should bee choosen?
no
25<37<49
37 is mean of 25 and 49
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what u say!? if i know 25<37<47 then how i can approximate ln37?
i only know ln2=.67 and then want to approximate ln 37
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