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find the indicated limit:
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lim x->2+ \[\frac{ 7\sqrt{x-2^{3}} }{ x-2 }\]
Your function isn't even defined at or around 2=x since x-8>=0 when x>=8 and 2 is definitely no in that interval
i dont get it
You have x-8 inside that square root
sqrt(x-8) exists over the reals when x-8>=0
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Domain for that expression is \([8,\infty)\) There is nothing at around x=2
You could have meant a different function though. Look at what you wrote and confirm that is or isn't the function we should be looking at.
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