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how do you find the side lengths of a 30 60 90 triangle?
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By using \(\text{Pythagorean Theorem..}\)
Or more precisely, with pen and paper and hands too.. :
sin(30 degrees)=1/2 Hypotenuse is 2, the side opposite the 30 degree angle is 1 and the remaining side is\[\sqrt{3} \]
Where is xx109 ?
use one angle and find ratio of any two side
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|dw:1413138739762:dw|
sin30=1/2=perpendicular/hypotenuse=a/b
cos30=base/hypotenuse=a/c
\[\frac{ 1 }{ 2 }=\frac{ a }{ b }\] \[b=2a\]
\[c=\frac{ a }{ \frac{ \sqrt3 }{ 2 }}\]
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now use cosine formula
u know cosine formula
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