Question

How do I solve for y? 2y^2-4y*sinx+2(sinx)^2+tanx=2

Answer 1

quadratic formula ;-;

Answer 2

But why is the answer in the book \[y=\sin x-\sqrt{1-\frac{ \tan x }{ 2 }}\]

Answer 3

Instead of \[y=\sin x+\sqrt{1-\frac{ \tan x }{ 2 }}\]

Answer 4

@hartnn

Answer 5

no idea, sorry, according to me it should say \(\pm \)

Answer 6

Okay, you know what? According to me, it should be +/- like you said. Thanks for the help.