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WILL FAN AND MEDAL!!! Simplify sine theta over square root of the quantity 1 minus sine squared theta.
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@ganeshie8 @bibby
@texaschic101 @dannyrod2000
@kropot72
\[(\sin \theta )\div (1 - \sin^2 \theta )\] ??
ohh k sq root....got it...wait
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so sin theta / sqrt. cos^2 theta............ then \[(\sin \theta) \div (\cos \theta) = \tan \]
@cambam1323
@cambam1323 ...........u got it?
no. these are the answer choices.... tan Θ tan2 Θ 1 −1
sorry, its tan theta tan^2 theta 1 -1
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yea.....i meant tan theta
so it's A
okay thank you!
mah pleasure
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