Question

solution or no solution?

4(3m+4)=2(6m+8)

5x+2x-3=-3x+10x

-(3z+4)=6z-3(3z+2)

-2(j-3)=-2j+6

Answer 1

if you get a value of variable than yes its solution
if variable cancel out then yes its no solution

Answer 2

the first one is solution>>>>>>> 12m+16=12m+16
the second one is no solution>>> 7x-3=7x
the third one is no solution>>>>> -3z-4=-3z+2
the fourth one is solution>>>>>> -2j+6=-2j+6

Answer 3

omg thanks so much i tried but i wasnt sure if i was doing it right! :)

Answer 4

no problem!

Answer 5

First one is an identity, with an infinite number of solutions.

Answer 6

Second one is inconsistent with no solution.

Answer 7

Third one is inconsistent with no solution.

Answer 8

The last one is an identity with infinite number of solutions.

Answer 9

Just test them out you will discover the problems.