Starting from rest, a 2.97 kg block slides 2.44m down a rough 39.4 degree incline. The coefficient of kinetic friction between the block and the incline is 0.471.
The acceleration of gravity is 9.8m/s^2.
A) Find the work done by force of gravity.

Ok so what I'm asking for is not the answer,
but why when solving for work the equation is...
w=mgsin(39.4)x == w=(2.97*9.8)sin(39.4)2.44
What I'm wondering is why it isn't negative? lol.
if you break it into components the y component is pointing downwards right? Or am I getting the concepts wrong...? Please and thank you!

Question

Starting from rest, a 2.97 kg block slides 2.44m down a rough 39.4 degree incline. The coefficient of kinetic friction between the block and the incline is 0.471. 
The acceleration of gravity is 9.8m/s^2. 
A) Find the work done by force of gravity.

Ok so what I'm asking for is not the answer,
but why when solving for work the equation is...
w=mgsin(39.4)x ==> w=(2.97*9.8)sin(39.4)2.44
What I'm wondering is why it isn't negative? lol. 
if you break it into components the y component is pointing downwards right? Or am I getting the concepts wrong...? Please and thank you!