Question

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution set of this problem?

Answer 1

n\[N \le -21\]

Answer 2

you would take \[5(N+27)\ge 6(N+26)\] and you would get \[5N+135\ge 6n+156\] then solve that and you get \[-N \ge 21\] so that would make your answer \[N \le 21\]

Answer 3

hopefully that helped c;

Answer 4

it did