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OpenStudy (anonymous):
How do I solve this?
Which of the following is a solution of x2 + 5x = -2?
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hartnn (hartnn):
solved a quadratic equation before ?
know about quadratic formula ?
OpenStudy (anonymous):
Yes and yes :)
hartnn (hartnn):
so,
you know you need
a,b,c values
what did you get them as ?
OpenStudy (anonymous):
a=2 b=5 and c=-2?
hartnn (hartnn):
almost correct! :P
but the form is
\( ax^2 +bx+c = 0 \)
so try again for 'c' value
a,b are correct :)
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hartnn (hartnn):
actually 'a' is also incorrect
OpenStudy (anonymous):
So would a=1 and c=0?
hartnn (hartnn):
a=1 yes
x^2 +5x+2 =0
c= 2
makes sense ?
OpenStudy (anonymous):
Ohh okay I see, yes :)
hartnn (hartnn):
have the formula with you?
start plugging in! :)
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OpenStudy (anonymous):
Okay so -5 is on the outside and 5^2 -4 (1)(2) over 2 is under the square root sign?
hartnn (hartnn):
go on
hartnn (hartnn):
what is 5^2 - 4(1)(2) =... ?
OpenStudy (anonymous):
Do you multiply the 1 and 2 by -4?
hartnn (hartnn):
yes
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OpenStudy (anonymous):
So 25-8?
hartnn (hartnn):
correct
OpenStudy (anonymous):
So now do I find the square root of 17 and divide it by 2 or is that the answer?
hartnn (hartnn):
you're done
|dw:1413220655632:dw|
^^ final answer :)
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