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Calculus1
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Put in y for f(x). Try any number (1-5... but doesn't matter) in for x
y = x^2 - 4x + 5 when x = 0, y = 5. So (0,5) is a point. It is the y-intercept. put x = 1, 2, 3, ...
So for example, 0. 0^2 - 4(0) + 5 = 5
The point would be (0,5). Put a dot (0,5) on the graph. Then try another number. Then draw a dot on that point on the graph. Then connect the two to make a line. (Don't forget to put arrows at the end of the line to show that the line continues forever)
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