A ladder of length 2x+1 feet is positioned against a wall such that the bottom is x−1 feet away from a wall. The distance between the floor and the top of the ladder is 2x feet.

Find the length, in feet, of the ladder.

Question

A ladder of length 2x+1 feet is positioned against a wall such that the bottom is x−1 feet away from a wall. The distance between the floor and the top of the ladder is 2x feet.
 
Find the length, in feet, of the ladder.

anonymous · Answer

(2x+1) is the length of ladder which is the hypotenuse 
2x is one leg
and x-1 is the other leg 
(2x)^2+(x-1)^2= (2x+1)^2 

 
4x^2+x^2-2x+1=4x^2+4x+1 
x^2-6x=0
x^2=6x 
x=6 Or x=0
x cannot be 0 
5,12,13

anonymous · Answer

What is the 5,12, and 13 at the bottom?

anonymous · Answer

@mikaylabean

anonymous · Answer

I see that you got that work from algebra.com, i just don't see where they get 5,12, and 13.

anonymous · Answer

Okay. I see their error. One second.

anonymous · Answer

Nevermind, I got it. That was right. Thank you!

anonymous · Answer

Mmhm!