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OpenStudy (anonymous):
Verify the identity. cot (x minus pi divided by two) = -tan x
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OpenStudy (anonymous):
@mathmath333 help?
OpenStudy (anonymous):
@amistre64 help please?
OpenStudy (anonymous):
@AnswerMyQuestions @Algorithmic @ilovebmth1234 @stgzlg
OpenStudy (anonymous):
@Algorithmic help please?
OpenStudy (gorv):
\[\cot(x-\pi/2)=-tanx\]
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OpenStudy (gorv):
is it your Q??
OpenStudy (anonymous):
Yes
OpenStudy (gorv):
here is trigonometric formula for cot Cot(A-B) = (CotACotB+1)/(CotB-CotA)
OpenStudy (gorv):
\[\cot(x-\pi/2)=\frac{ cotx*\cot (\pi/2) +1}{ \cot (\pi/2)- cotx }\]
OpenStudy (gorv):
cot(pi/2)=0 standard value =(0+1)/(0-cotx)
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OpenStudy (gorv):
\[=\frac{ 1 }{ -cotx }=-tanx\]
OpenStudy (gorv):
as cotx=1/tanx trigonometric value
OpenStudy (anonymous):
You are a life saver. Thank you so much!! I'll give you a medal :)
OpenStudy (gorv):
hahhaha....:D
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