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The sum of four consecutive integers is 226. What is the THIRD integer?
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here; x+2x+3x+4x=226
x is any integer
10x=226 gives x=22.6
x + x + 1 + x + 2 + x +3 = 4x + 6 = 226
Subtract 6 from each side of the equation and you end up with 4x = 220. The divide each side by 4
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can anyone help me with MY question THAT I POSTED
and you get 55. So the four consecutive numbers would be 55, 56, 57, and 58. What is the third number listed?
57
lol, is this not the question you posted?
and yeah that's right
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thanks
you're welcome
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