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Show that (1-i) is the square root of -2i.
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You have to show that \[\Large 1-i = \sqrt{-2i}\] equivalently, you can show that \[\Large (1-i)^2 = -2i\] I squared both sides to get that second equation
Recall (a+b)^2=a^2+2ab+^2 and not a^2+b^2 Just a reminder
@iTiaax any thoughts? or you fainted ?
@jdoe0001 , It's all good! I had no idea how simple this was :O
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