Question

I need help quick please!
Which of the following are solutions to the equation sinxcosx=sqrt(3)/4?

1. pi/12 +npi
2. pi/6 +npi
3. pi/12 +npi/2
4. 2pi/6 +npi

I think the answers are 2&3.

Answer 1

recall sin(x)cos(x)=.5*2sin(x)cos(x)=.5sin(2x)

Answer 2

So am I right with 2&3

Answer 3

How did you get 3?

Answer 4

i dont know can you help me?

Answer 5

\[\sin x.\cos x = \frac{\sqrt{3}}{4}\]
\[\frac{1}{2} 2 \sin x.\cos x = \frac{\sqrt{3}}{4}\]
\[\sin 2x = \frac{\sqrt{3}}{2}\]
\[x = \frac{1}{2} \sin^{-1} (\frac{\sqrt{3}}{2})\]

Answer 6

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