Question

Who can help i just can't seem to solve this problem

Answer 1

http://www.tutorpace.com/guest/classroom/4463

Answer 2

anyone can you guys help please I'm struggling to get the correct answer

Answer 3

\[\frac{ x }{ 3 x-9 }-3=\frac{ 1 }{ x-3 }\]
\[\frac{ x-9x+27 }{ 3x-9 }=\frac{ 1 }{ x-3 }\]
\[(-8 x+27)(x-3)=3x-9\]
\[-8 x^2+24x+27x-81=3x-9\]
\[-8x^2+51 x-81-3x+9=0\]
\[-8 x^2+48 x-72=0\]
\[x^2-6x+9=0\]
\[(x-3)^2=0,x=3\]
the equation does not hold when x=3
so it is an extraneous root.