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Help with Algebra 2? Solve the system using substitution or elimination. The answers are given as (x,y,z).
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add the second and third equations to get rid of z, and subtract the first and third ones to again get rid of z.
Answer Choices: (1,-3,0) (-3, 3, 0) (-31/5, 11, -3) (1, -3, 12)
By now you have two equations that you should be able to solve easily by whichever method you want
-x-2y=5 x+y=-2
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solve for x and y, then plug back into one of the original 3 equations to find z
@M0j0jojo
@bloofoffiction
so it would be (1,-3,0)? @ertdre
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