Question

Check my factoring work please??

Factor completely: 3x^3y +6^2y^3

my work:
3x^3y +6^2y^3
(3)(1)x^3y + (3)(2)^2y^3
3(x^3y + 2^2y^3)

Answer 1

instead of 3x^3y +6^2y^3

did you mean 3x^3y +6x^2y^3 ??

Answer 2

yes! sorry

Answer 3

\[\Large 3x^3y + 6x^2y^3\]

\[\Large 3x^2*x*y + 2*3*x^2*y*y^2\]

\[\Large 3x^2y*x + 3x^2y*2y^2\]

\[\Large {\color{red}{3x^2y}}*x + {\color{red}{3x^2y}}*2y^2\]

\[\Large {\color{red}{3x^2y}}(x + 2y^2)\]

\[\Large {\color{black}{3x^2y}}(x + 2y^2)\]

Answer 4

As a check, you can distribute the \(\Large 3x^2y\) back through and you should get \(\Large 3x^3y + 6x^2y^3\) back again