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Calculus1 17 Online
OpenStudy (anonymous):

how do you find the antiderivative of (1-x^2)^(1/2)?

OpenStudy (aum):

Make the substitution \(x = \sin(\theta)\)

OpenStudy (anonymous):

Use the reverse power rule, imo it's easier than u substituting for this one: Reverse Power Rule is x^(n+1)/n+1

OpenStudy (xapproachesinfinity):

nope you can't use that! U sub is your saver

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