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OpenStudy (anonymous):
What is the antiderivative of sin2x/cosx?
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geerky42 (geerky42):
HINT: \(\sin(2x) = 2\sin(x)\cos(x)\)
OpenStudy (anonymous):
ok, so then 2sinxcosx/cosx?
OpenStudy (anonymous):
set u=cosx
geerky42 (geerky42):
You now can cancel \(\cos(x)\) out.
OpenStudy (anonymous):
oh yeah..
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OpenStudy (anonymous):
so then it's just the antiderivative of 2sinx?
geerky42 (geerky42):
Yeah
OpenStudy (anonymous):
so it's -2cosx
geerky42 (geerky42):
+C
OpenStudy (anonymous):
yup
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OpenStudy (anonymous):
thank you
geerky42 (geerky42):
No problem
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