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how many integral solution are possible x^2+y^2+z^2=1980 some hw for everyone
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are we allowed to use this http://en.wikipedia.org/wiki/Legendre's_three-square_theorem
u can use whatever u want
then we're done
1980 = 4x495 = 4(8*61 + 8) appealing to Legendre's three square theorem, you can conclude there are no solutions
yeah u r right
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4(61*8+7) :p
thatzz understandble jst typin mistake
its a bit boring way to work a problem... i feel working it without using the theorem will be mrore interesting..
but that will like hit and trial
you have to pick number ending with 0 and try
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like a0, b0 ,c0
a b and c are any integer
now on squaring these they will give 2 zeros in end
so no possible solution
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