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Mathematics 13 Online
OpenStudy (anonymous):

A force of 400 Newtons stretches a spring 2 meters. A mass of 50 kilograms is attached ot the end of the spring and is initially released from the equilibrium position with an upward velocity of 10m/s. After finding the equation of motion, caculate x(t=pi/12).

OpenStudy (perl):

use the equation F = -k*x

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