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There are 15 technicians and 11 chemists working in a research laboratory. In how many ways could they form a 5-member safety committee if the committee must have exactly one technician?
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25C5
11+15 = 26 (-1) technician = 26-1 = 25 (25)! / [(25-4)! (4)!
12650
that is not right.
I realized i have not learned this part of the lesson yet, and my teacher is going to be going over it tomorrow
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btw the answer is 15C1*11C4=4950
Oh my bad . I was thinking permutation and applied combination. Thanks for pointing out.
No problem, we all make mistakes ;)
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