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how do i solve 2D?
how did you find 1a)
i used the distance formula with the points (4,2) and (4,-3)
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arcAB is given....thus
so now we need the far arc?
would the far arc be 260?
well.... AC and BC are both tangents to the circle... not secants... so that makes the "far arc" pretty obvious I'd think
yeap, 260 degrees
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ok i got it from here, thank you!!! :-)
yw
the answer is 80, correct?
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