Question

The parabola given by the equation y = -x^2 + 14 x - 5 has its vertex at (h,k) for

Answer 1

\(\bf \textit{vertex of a parabola}\\ \quad \\
y = {\color{red}{ -1}}x^2{\color{blue}{ +14}}x{\color{green}{ -5}}\qquad


\left(-\cfrac{{\color{blue}{ b}}}{2{\color{red}{ a}}}\quad ,\quad {\color{green}{ c}}-\cfrac{{\color{blue}{ b}}^2}{4{\color{red}{ a}}}\right)\)