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Mathematics 9 Online
OpenStudy (pinknabastak):

the road runner steps off a ledge and drops to the ground in 0.50s What is the Runners velocity the instant it hits the ground? How high is the ledge off the ground?

OpenStudy (perl):

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OpenStudy (perl):

g has units in meters / second^2 or feet / second^2 , which would you prefer ?

OpenStudy (perl):

g is the acceleration constant (due to gravity)

OpenStudy (pinknabastak):

so d=1/2(9.8)(0.5)^2

OpenStudy (pinknabastak):

so the distance is 1.2 m..how would i get the velocity?

OpenStudy (perl):

we can use the formula vf = vi + a*t , vf is final velocity, vi is initial velocity, a is acceleration

OpenStudy (perl):

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