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(b^4)^2
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simplify ?
if simplification then , b^8
\((b^4)^2\) Squaring it means multiply it by itself, so you have \((b^4)^2 = (b^4)(b^4)\) You are multiplying b times itself 4 times by b times itself 4 times; So \((b^4)(b^4) = (b\cdot b\cdot b\cdot b)(b\cdot b\cdot b\cdot b)\\~~~~~~~~~~~~~~=b\cdot b\cdot b\cdot b\cdot b\cdot b\cdot b\cdot b\\~~~~~~~~~~~~~~=\boxed{b^8}\) Shortcut is adding exponents: \((b^4)(b^4)=b^{4+4}=b^8\) Shortcut to this entire thing is multiply exponents: \((b^4)^2 = b^{4\cdot2}=\boxed{b^8}\) Makes sense?
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