Question

FIND THE DERIVATIVE OF SQUARE ROOT OF 3+4X

Answer 1

Have you considered the Chain Rule?

Answer 2

d/dx √(3+4x)
= f'(g(x))*g'(x) [chain rule]
1/2 (3+4x)^(1/2 -1) * 4 g'(x)=g'(3+4x) = 0+4=4
(1/2)(3+4x)^(-1/2) *4
2(3+4x)^(-1/2) 0r 2/√(2+4x)

Answer 3

2 / radical ( 3+4x)