Question

cos(t)=1/5 what is csc(t)

Answer 1

\(\bf cos(t)=\cfrac{1}{5}\to \cfrac{adjacent}{hypotenuse}\to \cfrac{a=1}{c=5}
\\ \quad \\
c^2=a^2+{\color{blue}{ b}}^2\implies \pm\sqrt{c^2-a^2}={\color{blue}{ b}}
\\ \quad \\
recall\implies csc(\theta)=\cfrac{hypotenuse}{opposite}\to \cfrac{c}{{\color{blue}{ b}}}\)