Mathematics
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OpenStudy (anonymous):
Suppose you roll two dice. Find the probability of not rolling a sum of 6
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OpenStudy (anonymous):
@MAli13chineta
OpenStudy (anonymous):
@Mandre
OpenStudy (anonymous):
@WolfMaster
OpenStudy (anonymous):
...?
OpenStudy (anonymous):
what?
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OpenStudy (anonymous):
@AdmiralAngel25 @abb0t @amistre64
OpenStudy (anonymous):
can u help me wolf i ain understandin
OpenStudy (anonymous):
shes asking for help. @WolfMaster
OpenStudy (anonymous):
0-0
OpenStudy (anonymous):
it's not like im interested in a wolf
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OpenStudy (anonymous):
lol
OpenStudy (anonymous):
Nice, so I show up 3rd when you press a? :D
OpenStudy (anonymous):
yea ;)
OpenStudy (anonymous):
well 4th
OpenStudy (anonymous):
i'm way down in the b's but any ways who is smart and can help
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geerky42 (geerky42):
@MAli13chineta 's explanation doesn't help?
OpenStudy (anonymous):
i know especially if ur not Einstein
OpenStudy (amistre64):
determine how many ways there is to get a sum of 6
OpenStudy (anonymous):
5 ways
OpenStudy (anonymous):
i mean 4
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OpenStudy (amistre64):
lets chk that
15
24
33
42
51
yep 5 ways
and how many outcomes are there entotal?
OpenStudy (anonymous):
i mean 5 again my b
OpenStudy (anonymous):
yea thts wut i got
OpenStudy (amistre64):
do we agree that there are 36 outcomes total?
OpenStudy (anonymous):
yea
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OpenStudy (amistre64):
the the prob of actually rolling a sum of 6 is 5/36
since all probs add up to 1, the rest of the probs are what does NOT add to 6
P(not6) = 1 - 5/36
OpenStudy (anonymous):
5 ways so 5/36 possibly
OpenStudy (anonymous):
what do u mean 1-5/36
OpenStudy (amistre64):
subtract what is 6 from 1, to determine what is NOT 6
OpenStudy (amistre64):
what is 1 - 5/36
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OpenStudy (anonymous):
0.86
OpenStudy (amistre64):
P(6) + P(not6) = 1
therefore
P(not6) = 1 - P(6)
OpenStudy (amistre64):
about .8611 yeah
OpenStudy (amistre64):
31/36 to be precise
OpenStudy (anonymous):
thx
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OpenStudy (amistre64):
youre welcome