-2x^2-20x+16 middle term break please help
sum of middle term = -20 and product of trem broken = -32
can u do that??
can you please solve?
i can guide
well use quadratic formula
u know abt that??
are you sure about the question ? you won't be getting integer solutions so you cannot split middle term
yeah i know about it
can u apply it for finding x
use quadratic formula or completing the square method whichever you're comfortable with
but i have forgotten the quadratic formula
Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
can you guide me how to put values in that
first find a,b,c to simplify calculations, you can also factor -2 initially from your equation
okay i am working on it
thnx for your help
\(-2 (x^2+10x-8)\) compare x^2+10x-8 with ax^2 +bx+c
a=-2, b=20,c=8
no.. you're taking x^2+10x-8 right ?
yeah
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