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Mathematics 15 Online
OpenStudy (anonymous):

Sorry, I am horrible at Math(: Help me maybe? This is the graph http://static.k12.com/calms_media/media/1312500_1313000/1312643/1/99a45d74ac85e7c581b85f02ff88f26b08902e7d/HS_A1G2_S1_07_10_ART3.jpg But, Which is the equation of the given line? Thank you.

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

@satellite73

OpenStudy (camerondoherty):

Any options?

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

x = -3

OpenStudy (anonymous):

b. x = 3 c. y = -3 d. y = -3x

OpenStudy (anonymous):

@camerondoherty

OpenStudy (camerondoherty):

Im actually not sure... The options just confuzzled me >.< srry

OpenStudy (anonymous):

... .

OpenStudy (anonymous):

in short it is a line parallel to x-axis and at a distance of 3 below x-axis so it is y=-3

OpenStudy (anonymous):

you can also use the formula \[y-y _{1}=\frac{ y _{2} -y _{1}}{ x _{2}-x _{1} }\left( x-x _{1} \right)\]

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