Mathematics
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OpenStudy (anonymous):
Question on circle [2]
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OpenStudy (anonymous):
Find equation of circle concentric with
\[\huge 3x^2 + 3y^2 -5x -6y -14 =0 \]
and perimeter of it semicircle is 36
hartnn (hartnn):
from the euqation, get the centre
hartnn (hartnn):
from the semicircle perimeter , get the radius
OpenStudy (anonymous):
after that
hartnn (hartnn):
what radius u got ?
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OpenStudy (anonymous):
i have to do 1 second
hartnn (hartnn):
perimeter of semicircle = pi r
OpenStudy (anonymous):
wait i was doing incorrectly
60/pi
OpenStudy (anonymous):
i was finding radius from the equation
hartnn (hartnn):
36/pi!
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OpenStudy (anonymous):
fuk sry
OpenStudy (anonymous):
i am trying to stay up late at night so bare with me please
OpenStudy (anonymous):
yes radius is
36/pi
hartnn (hartnn):
and centre ?
OpenStudy (anonymous):
(5/3 , 2 )
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hartnn (hartnn):
5/3 ?
hartnn (hartnn):
2? :O
hartnn (hartnn):
from where are u getting those numbers ?
OpenStudy (anonymous):
i divided the equation by 3 and center is (-g , -f ) right?
hartnn (hartnn):
but the original equation has
2gx and 2hy
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OpenStudy (anonymous):
(5/6 , 1 )
hartnn (hartnn):
2g = -5/3
and yes, now correct :)
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
hello , r u there
OpenStudy (anonymous):
@hartnn
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hartnn (hartnn):
yes
OpenStudy (anonymous):
after thst
OpenStudy (anonymous):
that*
hartnn (hartnn):
you have center
you have radius
what else do u need ? :O
hartnn (hartnn):
\((x-h)^2+ (y-k)^2 =r^2\)
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OpenStudy (anonymous):
so the semi circle was of the larger circle ,]
got it